Hi I have a question on the gradient of the curve.

Find the equation of the tangent to the following curve at the point indicated.

y=θ² - 3sin θ where θ=π/3

i have differentiated the above function then tried to gradient at π/3, then i tried to find the value of y at π/3. Setting up the equation of gradient
y-y(1)=m(x-x(1)).

the answer should be

18y=(12π-27)x+9π-2π²-27√3

Question

Hi I have a question on the gradient of the curve.

Find the equation of the tangent to the following curve at the point indicated.

y=θ² - 3sin θ   where θ=π/3

i have differentiated the above function then tried to gradient at π/3, then i tried to find the value of y at π/3. Setting up the equation of gradient
 y-y(1)=m(x-x(1)).

the answer should be 

18y=(12π-27)x+9π-2π²-27√3

anonymous · Answer

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Did u get it?

anonymous · Answer

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