Find the value of n + 6 http://static.k12.com/eli/bb/811/7537/0/2_36640_44211/7537/cfcbab7622b25115e3996826ebe54350776a6601/media/4f8a76aa40c8dbfbdd18208b34c6ed719fba027b/mediaasset_650550_1.gif 132 113 62 119
@Shanks i know you can help me with this problem
ok, wait :P
ok
btw u give thought to ur problem, or just ask right away? lol
i think about it and if i dont know how then i come here
for this you need to remember that: Sum of angles of a polygon of n sides = 180(n-2) A triangle, square, parallelogram, 5 sided figure...all are polygons. For a triangle, n=3; for sq, n=4....and so on. here n=6 so sum of angles = 180(6-2) also equal to 135+62+151+140+n+(n+6) now find the value of n from this eqn and then find (n+6) PS: the basic thing is sum of angles of n sided polygon = 180(n-2)
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