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What is the limit for lim (t+∆t)²-8(t+∆t)+3-(t²-8t+3)/∆t ∆t→0
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open brackets . solve ityou'll get terms in delta t . simply divide and put deta t =0 . ,. 2t-8
is delta arbitrary? It doesn't mean change?
no man .. that delta denotes a small value . i.e . if i write delta t . that means very small value. delta don't have any sense if written alone . don't consider it separate variable
delta t is one symbol. often people use h instead
ohh i see, that makes it a lot more clear. Thanks a lot guys
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