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(1)/(x+2) + (x-2)/(x-5) + (4x+3)/(x^2-3x-10)
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ok. i m trying to solve it
\[\frac{ 1 }{ x+2 }+\frac{ x-2 }{ x-5 }+\frac{ 4x+3 }{ x ^{2}-3x-10 }\]
\[=\frac{ 1 }{ x+2 }+\frac{ x-2 }{ x-5 }+\frac{ 4x+3 }{ x ^{2}-5x+2x-10 }\]
r u following me
\[=\frac{ 1 }{ x+2 }+\frac{ x-2 }{ x-5 }+\frac{ 4x+3 }{ (x+2)(x-5) }\]
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\[=\frac{ x-5+x ^{2}-4+4x+3 }{ (x+2)(x-5) }\]
and so on
if u need more help plz ask me
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