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OpenStudy (miamiamia):
Please help: Find all solutions in the interval [0, 2pi). cos^2x + 2 cos x + 1 = 0
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OpenStudy (anonymous):
Solve it like you would solve a quadratic iirc
OpenStudy (anonymous):
cos^2x + 2 cos x + 1 = 0 (cosx +1)^2 =0 cosx+1=0 cosx= -1 x=pi
OpenStudy (miamiamia):
thank you!! :)
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