Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1). (explain show steps)

Question

anonymous · Answer

3x + y = 7

y = -3x + 7

m1 = -3

Perpendicular m1*m2 = -1

-3 * m2 = -1

m2 = 1/3



Nw using point Slope Form.... (6, −1)

y-y1 = m2(x-x1).....Hope nw u can Solve..

anonymous · Answer

y+1 = 1/3 ( x-6).......Just Solve.....)

anonymous · Answer

confused?

y =1/3x − 3

 y =1/3x + 17

 y = −3x − 3

 y = −3x + 17

anonymous · Answer

y =1/3x − 3

anonymous · Answer

thank you and how did you get that?