Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1). (explain show steps)

Answer 1

3x + y = 7

y = -3x + 7

m1 = -3

Perpendicular m1*m2 = -1

-3 * m2 = -1

m2 = 1/3



Nw using point Slope Form.... (6, −1)

y-y1 = m2(x-x1).....Hope nw u can Solve..

Answer 2

y+1 = 1/3 ( x-6).......Just Solve.....)

Answer 3

confused?

y =1/3x − 3

y =1/3x + 17

y = −3x − 3

y = −3x + 17

Answer 4

y =1/3x − 3

Answer 5

thank you and how did you get that?