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sec x sin2x is equivalent to.. 1/2, 2cosx, 2,2sinx explain please.
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\[\sec x = \frac{ 1 }{ cosx }\]
\[\sin2x = 2sinxcosx\]
now just multiply both of them you will get the answer.
(1/cosx)(2sinxcosx)
i dont really know how to multiply, the sin and cos confuse me
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hmmm \[\frac{ 2sinxcosx }{ cosx }\] can you see soemthing common that can be ccancel out?
oh...that was easy
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