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MIT 6.002 Circuits and Electronics, Spring 2007 15 Online
OpenStudy (anonymous):

ques 6 : V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω. please tell the ans if any one has right one..one attemp remaining,,please

OpenStudy (anonymous):

time constant is 0.1 ms for both rising and decaying signal, and 7.9v as vmax and o.164 as v min

OpenStudy (anonymous):

hello ebein can you give formula's for that question???

OpenStudy (anonymous):

for rising its iL = vS/(RW+RL)*(1-e^-((RW+RL)*t/L)) and decaying is as follows vL = iL*RL*e^-((RW+RL)*(t-T)/L)

OpenStudy (anonymous):

0.534volt second part

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