Question

anyone can explain how this?
( (1/(1-2sin²θ)))-1 / ((2sinθ)/(1-2sinθ)) <-----?? = sinθ
become this?
((1-1+2sin²θ)/(2sinθ))=sinθ

Answer 1

Is this the expression you've got:\[\frac{ 1 }{ 1-2\sin^2 \theta }-\frac{ 1 }{ \frac{ 2\sin \theta }{ 1-2\sin \theta } }=\frac{ 1 }{ 1-2\sin^2 \theta }-\frac{ 1-2\sin \theta }{ 2\sin \theta }\]