Question

pre-calc trig
find all solutions to the equation
7 sin^2x - 14 sin x + 2 = -5

Answer 1

Replace \(\sin^2(x) \) with \(u^2\) and \(\sin(x)\) with \(u\).
Quadratic equation right there

Answer 2

do I add the -5 to the 2?

Answer 3

bc quad equations always = 0 right?

Answer 4

Yes

Answer 5

then we end up with (u-1) (7u-7)

Answer 6

then I switch the u back to sin x right?

Answer 7

mhm

Answer 8

no, first for \(u\)

Answer 9

wait, yeahso we end up with sinx=1 and sinx=1...?

Answer 10

Yes, :)

Answer 11

And you can do it

Answer 12

ahh this is the part I get mixed up in :/