Question

Find the equation in standard form which passes through (3, –6) and (–2, –1). You must show all work.

Answer 1

(3,-6)-(-2,-1)

To calculate the equation of the line, use the y=mx+b format.

m=(-1-(-6))/(-2-(3))

y=mx+b

(-6)=(-1)*(3)+b

b=-3

y=-x-3

Answer 2

wait is that the answer or do i need to solve it @Luis_Rivera

Answer 3

what else do you need. its solved and answrd !

Answer 4

no im sorry i thought their was more thank you @Luis_Rivera

Answer 5

kk :)

Answer 6

@MilaCoolNess plz close the question :)

Answer 7

@Aperogalics im reviewing it ill close it when im done

Answer 8

k :)