Question

This may seem stupid but can anyone help??
I have to divide 10 by 5 minutes and 54 seconds????

Answer 1

@nubeer

Answer 2

Heh, I get it.

Answer 3

\(5 \min 54 \sec = 5 \dfrac{54}{60} = 5.9\)

Answer 4

Is it this?

Answer 5

@ParthKohli

Yeah right.

Answer 6

Im doing a Algebra2 experiment and i have to divide my average time by 10
Here are my times
5 min 54 sec
4min 55sec
3min 30sec

so when i divide these all by 10 do i put the time in decimal form? Like 5min 54 sec= 5.54??

Answer 7

Essentially, \(5 \min 54 \sec = {5 } + \dfrac{54}{60}\) as we're expressing the seconds as a fraction.

Answer 8

Now, you can simplify \(\dfrac{54}{60}\).

Answer 9

so, 5.9 divide by 10? and i get .59? and that would be my awsner for that one

Answer 10

BTW, it'd be dividing 5 min 54 sec by 10, not the vice-versa.

Answer 11

Yes, that'd be your answer :) @julliemyers

Answer 12

oh ok then so just to make sure i get the rest correct let me do them and will u check them?

Answer 13

hmm it says to divide the average time by 10.. so that might not be the answer.. first you have to convert all your times into decimal

Answer 14

Sure! =)

Answer 15

((10/5) minute) + (54 seconds) = 2.9 minutes

Answer 16

Oh, yes.

Answer 17

Didn't see that question below.

Answer 18

no i had 3 trials and i have to divide 10 by indivaual times

Answer 19

serach on google divide 10 by 5 minutes and 54 seconds

Answer 20

Okay... so can you divide the other times by 10 after converting them and take the average of all figures you get?

Answer 21

hang on ill show u my table

Answer 22

5 minutes 10 seconds divide it by 5 = 1 minute 2 seconds.

Answer 23

Oh, so that is the question.

Answer 24

this is the directions


. For each trial, use a stopwatch to record the number of
seconds it takes for the pendulum to complete 10 full swings. Record each time
in the i rst column of the table provided on the next page. Next, i nd and record
the average of the three times you listed. Finally, divide the average time by 10 to
determine the period of the pendulum. Repeat the procedure using two coins, then
using three coins, recording the data in the second and third columns, respectively.
Does it appear that the weight of the bob af ected the period of the pendulum?
What factors other than the weight might af ect the period of the pendulum?

Answer 25

So you have to find the average period. It'd be 5 min 54 sec by 10.

Answer 26

yes each collum had their own average time

Answer 27

Then I'm afraid you'd have to complete this experiment by yourself.

Answer 28

Did you do this experiment?

Answer 29

hmm ok i have a question.. something don't seem right.
in the trial 1 with 1 coin the time u have wrote is for 10 swings?

Answer 30

yes it was in the file i attatched
i just needed help on how i would divide time by 10

Answer 31

But that wouldn't be the time for 10 swings.
Though there's a cheat: You can divide it by 3. ;)

Answer 32

add all noted times with seconds as fraction and then divide by 10. here is your answer :)

Answer 33

@julliemyers wel i think the average time u have found for 10 swings in that file is wrong.. u need to check that again.

Answer 34

You can add 3 noted times and divide by 3 -- no one would realize :D

Answer 35

@nubeer: Seems like julliemyers has summed up the three noted times in the above rows.

Answer 36

yup she did that.. she just forgot to divide by 3

Answer 37

Mhm

Answer 38

@nubeer it doesnt say i need to divide by 3 tho?

Answer 39

i know it don't say and it will never say.. the Word Average itself says it..
Average = Total time/ no. of times experiment performed..
means you would add up the time of all the 3 trials and then divide it by 3..
IF INCASE.. there was a 4th trial then you would add all the 4 times and divide by 4... you have to do this where ever the average word comes up

Answer 40

ohh Yea i remeber that. So for ex 5 min 54sec would be 5.54/3 =1.846 then i devide that by 10?? =0.1846????

Answer 41

yes..

Answer 42

ok i think i have got it lol -.-

Answer 43

lol good :)

Answer 44

@julliemyers No

Answer 45

@ParthKohli No to what? Im wrong?????

Answer 46

lol that was 5.9 .. the total time.

Answer 47

It's not \(5.54\); it's \(5.9\)

Answer 48

And you don't have to further divide by 10.

Answer 49

Got it? :D

Answer 50

lol she have to divide by 10 to find the time period.. @ParthKohli

Answer 51

Im so confused (-.-)

Answer 52

First add all the time , trial 1,2,3 that would be 5.9 and divide it by 3.. the value you will get you will put that against this row "Average time complete 10 full swings"

Answer 53

Oh yes

Answer 54

Now.. the value in this row "Average time complete 10 full swings" you would divide it by 10 and put them in this row "Period of pendulum "

Answer 55

@nubeer: My medal increased your SS :P

Answer 56

lol does it ? really? hahah i dont think so.. lol i never work on medals but still thank you...

Answer 57

Im spose to have 3 periods of pendulum times, I dont think i add up all my averages. i think im spose to have 3

Answer 58

hmmm .. :( not getting you.. ok look the file you have posted and see the row average time for 10 swings what value u have in there?

Answer 59

yes those r the values added of the coin 1 coin 2 and coin 3

Answer 60

ok.. now 5 min 54 secs convert in decimal you will get 5.9 right? you did that before now divide 5.9 by 3... becasue that total time is for 3 trials.. getting it?

Answer 61

i get 1.966666666 = 1.97

Answer 62

so 1.97 would go in the period of pendulum collum???

Answer 63

ok.. good.. now this is average time for 10 swings.. ok?
now for the time period of pendulum.. this means the time period for just 1 swing so u divide 1.97 by 10

Answer 64

.197

Answer 65

yes

Answer 66

Should i have 5.9, 4.9, 3.5In the average collum? Instead of the minutes and seconds or should i leave it how it is

Answer 67

hmm i told u these are not average.. 5.9/3 would be the aveage so 1.97 mins is the average of 10 swings.

Answer 68

ok thats what i was wondering lol i feel stupid but i understand it now lol

Answer 69

lol no worries..

Answer 70

ok so i fixed it take a look

Answer 71

yup looks ok now.. this all are in mins. :)