Question

solve the given problem
Use the method of Fourier integrals to find the solution of initial value problem
with the partial differential equation.
pu/pt=c2p2u/p2t with initial condition u(x,0)=f(x)
note here p=partial derivative
and 2=square

Answer 1

So you're looking at:
\[\frac{\partial u}{\partial t}-c^2 \frac{\partial^2 u}{\partial t^2}=0\]? Or is the second partial with respect to x?