Question

Problem 3: scrabble
The function for checking whether a word is valid passes the test provided:
if word in word_list:
for k in range(0,len(word)-1):
if (word[k] in hand.keys()) & (word.count(word[k]) <= hand.get(word[k])):
return True
else:
return False
The main code seems to not implement correctly:
if not is_valid_word(word, hand, wordlist):
word = raw_input("Enter word, or a '.' to indicate that you are finished: ")
if word == '.':
print "Your total score is: " + str(score)
any ideas?

Answer 1

added the following under for loop
if word[k] not in hand.keys():
return False
That seems to fix it, but the function passes the test without it, so I think the test should include situations where the word contains letters that are not in the hand.