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\[(4t^2-1)/(15t + 10) \div(4t^2-4t+1)/(3t^2+5t+2)\]
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make sure you denominators are not zero
\[15t+10=0\iff t=-\frac{2}{3}\] so \(-\frac{2}{3}\) is out
\[3t^2+5t+2=0\] \[(3t+2)(t+1)=0\] \[t=-\frac{2}{3}, t=-1\] so those two are out
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and when you multiply, you have to take the reciprocal, so also solve \[4t^2-4t+1=0\]
are the restrictions the -2/3 and -1?
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