Question

The circuit parameters have the following values: VS=4V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V

Answer 1

p1: Vo=Vs since vin<vt
p2: v0 = vs-kr(e^((vin-vt)/vn)-1)
p3: vin = ln(vs/2kr +1)*vn+vt
p4: vin=sqrt(vs/kr)+vt
p5: -kre^((vin-vt)/vn)
p6: -kr(vin-vt)

p1: 4s
p2: 4-(1*1)(e^((2-1)/1)-1) === 2.281718
p3: ln(4/2*1*1+1)*1+1 === 2.0986
p4: sqrt(4/1)+1 === 3
p5: -e^((2-1)/1) === -e === -2.7182
p6:-(2-1) === -1