Question

A+B = 5 pie/4, ( (1+cotA) ( 1 + cotB) )/(cotAcotB) = ?

Answer 1

( (1+cotA) ( 1 + cotB) )/(cotAcotB)
= (1+cot A + cot B + cot A cot B) / cotA cot B
now separate the denominator.

Answer 2

tanAtanB + TanA + tanB + 1

Answer 3

what ?

Answer 4

= (1+cot A + cot B)/cotAcot B + (cot A cot B) / cotA cot B
= (1+cot A + cot B)/cotAcot B + 1

Answer 5

that '1' will be a trouble...

Answer 6

cot (A+B) =.... ?

Answer 7

ok, lets work with tan
tan(A+B) = tan 5pi/4 = ... ?

Answer 8

tan 5pi/4=1

Answer 9

tan(A+B) = (tan A+tan B) /(1+tan A. tan B) = ...

Answer 10

tan(A+B) = (tan A+tan B) /(1-tan A. tan B)

Answer 11

oops,
tan(A+B) = (tan A+tan B) /(1-tan A. tan B) =1
which gives
tan A+tan B = 1-tan A tan B

Answer 12

so, tanAtanB + TanA + tanB + 1=...?

Answer 13

tanAtanB + TanA + tanB + 1= tanAtanB +1-tan Atan B+ 1=2

Answer 14

Yup... thxx...