Question

A particle is thrown vertically upwards with a speed of 50m/s the ratio of the distance travelled in 2nd second to the last second of its flight is?

Answer 1

T = 2u/g = 100/10 = 10s

Dn = u + a/2 (2n-1)

D2/D10 = (50 + 5*3)/(50+5*19) = 13/27....Is this Correct

Answer 2

last second = first second

Answer 3

i got my mistake..Since it is projected upwards a = -g...i took it as +g..)

Answer 4

it shuld be 50-15 / (50 + 5*19)