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simplify the expression: -5+i/2i
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\[\frac{5+i}{2i}\times \frac{i}{i}\] is a good start to rewrite in standard form
so then you get 5i^2/2i^2 = 5/2?
-5/2
\[\frac{-5+i}{2i}\times \frac{i}{i}=\frac{-5i-1}{-2}\] \[=\frac{1}{2}+\frac{5}{2}i\] in standard form
oh okay thank you I multiplied it wrong
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yw
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