Question

What is the expression in factored form?

x2 + 14x + 48
A. (x + 6)(x - 8)
B. (x + 8)(x - 6)
C. (x - 8)(x - 6)
D. (x + 6)(x + 8)

Answer 1

you need 2 numbers whose product is 48 and when
these are added get 14

Answer 2

find that numbers ?

Answer 3

D. (x + 6)(x + 8)

Answer 4

yes, correct ^

Answer 5

thx..please click best response if any people answer true...

Answer 6

\[x^2 + 14x + 48\]\[=(x+a)(x+b)=x^2+ax+bx+ab=x^2+(a+b)x+ab\]
\[\qquad\qquad\qquad 14=a+b\]
\[\qquad\qquad \qquad ab=48\]
all the pairs of factors of \(48\) are ;

\((\pm1)(\pm48),~(\pm2)(\pm24),~(\pm3)(\pm16),~(\pm4)(\pm12),~(\pm6)(\pm8)\)

\(a ~~\& ~~b\) are the factor pair that add to \(14\)