Question

Part 1 [3 points]: What are the possible number of positive, negative, and complex zeros of f(x) = –2x3 – 5x2 + 6x + 4 ?
Part 2 [4 points]: Use complete sentences to explain the method used to solve this equation.

Answer 1

Count the sign changes of f(x)

--++ (I get one)

Count the sign changes of f(-x)

+--+ (I get two)

Thus? One Positive Real and MAYBE two Negative Reals, but those two might be Complex.

See where those counts come from.