Question

What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth?

x ≈ −3.23 and x ≈ 0.23

x ≈ −2.72 and x ≈ −0.28

x ≈ 0.28 and x ≈ 2.72

x ≈ −0.23 and x ≈ 3.23

Answer 1

\[4x^2+3=-12x\]

Right ?

Answer 2

yup

Answer 3

Well then

\[4x^2+12x+3=0\]

Here

a=4

b=12

c=3

in Quad formula,
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Put the values and get your answer :)

Answer 4

@Vince34

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Answer 5

@Vince34

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