Question

The sum of 40 consecutive intergers is 100. What is the largest of these integers?

Answer 1

hi let it an integer is x

Answer 2

then x+x+1+x+2.........................x+40=100

Answer 3

if the 1st integer is x
then 40th integer = x+39
so, x+x+1+.....x+39 = 100

Answer 4

now, notice that there will be 40 'x's,
and the constants are 1+2+3+...38+39
to find, 1+2+3+...38+39
use, the formula for sum of first terms = \(n(n+1)/2\)
here n=39.
so, it'll be
40x+ 39*40/2 =100
or
40x + 20*39 = 100
now can u find 'x' from this equation ??