Find the area of a rectangle if the perimeter is equal to 38 in and the length is 10.
u must find its width, first
how do u do tht
do u know formula of the perimeter a rectangle
no can you please tell me
perimeter = 2(l+w) with l=length, w=width
so, u can make an equation : 2(10+w) = 38 solve for w
so it will be 2(9.5+10)= 39
nopes.. it should be 2(10+w) = 38 now, solve for w
w=18
nopes.. 2(10+w) = 38 both sides divided by 2, what u get ...
2 * 10 + w = 38 20+w=38 w=18
no, if u want multiply in bracket by 2, u must use distributive property : a(b+c) = a*b + a*c so, 2(10+w) = 2*10 + 2w = 20 + 2w
now, u have 20+2w=38
but that is not one of the choices I have on my homework
yeah, because this is not clear. after u found the velue of w, next u can determine the area by using the formula A=l*w
80?
90*
well, look this : 20 + 2w = 38 move 20 to right side, becomes 2w = 38-20 2w = 18 w = 18/2 = 9 so, the area (A) = l * w = 10 * 9 = ...
yup its 90 thank u so much
yup, very welcome
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