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Mathematics 13 Online
OpenStudy (anonymous):

what is tanx=2cscx in the interval of -pi

OpenStudy (shubhamsrg):

tanx = sinx/cosx cscx = 1/sinx now try..

OpenStudy (anonymous):

and sin^2 x + cos^2 x = 1 1 - cos^2 x = sin^2 x

OpenStudy (anonymous):

u have to find the General Solution..)

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