Question

what the point slope equation of the line with 3/2. that goes through the point (-3,5) ?

Answer 1

y-y1 = m(x-x1)

m= slope

Answer 2

\[y-y_1=m(x-x_1)\]

where,

m=3/2

(x1,y1)=(-3,5)

Answer 3

y + 5 = -3/2(x-3) ?

Answer 4

m=3/2 not -3/2

Answer 5

So,

y-5=3/2(x+3)

Answer 6

Now you can take 2 on that side


2(y-5)=3(x+3)

now solve