Question

Help :)

The fraction 1-1/a divided by 1-1/a^2 is equiv. to...
Solve for x: 3/x-2+8/x^2-4=1

Answer 1

For the first question try setting it up this way:

(1 - 1/a) / (1 - 1/a^2) = (a - 1)/a / (a^2 - 1) / a^2

Instead of dividing, multiply by the reciprocal, then rewrite a^2 - 1 as (a + 1)(a - 1).

You will find that most everything cancels.

As for the second question, try multiplying everything by x^2. That way you will get 3x - 2x^2 + 8 - 4x^2 = x^2

Answer 2

ok thanks

Answer 3

:)