Question

divisor=3
cand=3
count=2

while(count<1000):

if cand%divisor==0:
if cand==divisor:
cand=cand+2
divisor=3
count=count+1
print 'inside_if_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor)

else:
cand=cand+2
divisor=3
print 'inside_else_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor)
else:
divisor=divisor+1
print 'outside_else_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor)
prin

Answer 1

I feel like i'm close to getting PS1, but once my counter hits 999, it hits the first inside_if_statement again and thus adds 2 to the 1000th prime. I'm not sure of a way around this... Would someone mind taking a look?

Answer 2

what is the last print statement? i think there is some of your code missing.

Answer 3

my final print statement basically says "print cand"

Answer 4

figured it out--here's the working version:


divisor=3
cand=3
count=2

while(count<1001):

if cand%divisor==0:
if cand==divisor:
cand=cand+2
divisor=3
count=count+1
##print 'inside_if_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor)
if count==1001:
cand=cand-2
else:
cand=cand-1+1
else:
cand=cand+2
divisor=3
##print 'inside_else_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor)
else:
divisor=divisor+1
##print 'outside_else_statement counter '+str(count)+'cand '+str(cand)+'divisor '+str(divisor)
print cand

Answer 5

im glad i could help :P xD
now seriously : gj for figuring it out!:)and im sry i couldnt help cause i had no time:P maybe next time !