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find theta!
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\[\LARGE \sqrt{3}\sin \theta-\cos \theta=2\]
\(\LARGE (\sqrt{3}/2)\sin \theta-(1/2)\cos \theta=2/2 \)
you're the man!
now write cos a = \sqrt 3/2 ,sin a =1/2
where a=...?
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60
pi/3
no.
oh sorry!!
pi/6
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sin ... = 1/2 ?
yes.
30 degrees
what is \(cos 30sin \theta-sin30 cos \theta=..?\)
i messed up u,u
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sin(A-B)
|dw:1356774577698:dw|
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