Question

Logarithms! Wait for image please!

Answer 1

Part c!

Answer 2

hint : write \(2=\log_2 2^2\)

Answer 3

This is what I have done so far:
log_2 (x - 1)^2 = log_2 4 + log_2 (x+2)
(x-1)^2 = 4 + x + 2
x^2 - 3x - 7 = 0

Answer 4

Is that correct?

Answer 5

no....

Answer 6

(x-1)^2 = 4 ( x + 2 )
u got how ?

Answer 7

Oh wait is it: (x - 1)^2 = 4x + 8 or am I still wrong?

Answer 8

@hartnn

Answer 9

now correct.

Answer 10

So if I solve that I should be able to get the answer right?

Answer 11

Okay thanks! :)

Answer 12

yes, welcome ^_^