http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/a/assessments/Q-QuadrilateralsPolygonsUnitExam/Geometry_Unit5_Exam_Final_21q.gif
What is n?
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OpenStudy (hba):
Sum of interior angles =(n-2)*180
where n=6
OpenStudy (hba):
@DorelTibi
Start working.
OpenStudy (anonymous):
n = 247
?
OpenStudy (anonymous):
?
OpenStudy (anonymous):
Answer?
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OpenStudy (callisto):
Geometry Unit 5 Exam Final?!
OpenStudy (hba):
Yes.
OpenStudy (anonymous):
lol how did u know
OpenStudy (anonymous):
will they though
OpenStudy (anonymous):
?
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OpenStudy (hba):
If you cheat.
OpenStudy (anonymous):
Im not cheating though I just need help
OpenStudy (hba):
I am just trying to keep you out of trouble :)
OpenStudy (anonymous):
so should i delte this post
OpenStudy (hba):
No you are not cheating at all :)
Anyways back to the problem,
Sum of interior angles =(n-2)*180
=(6-2)*180
=
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OpenStudy (hba):
I know you can solve it further :)
OpenStudy (anonymous):
247=180n-360
607=180n
n= 3.372
OpenStudy (anonymous):
?
OpenStudy (hba):
Sum of interior angles=4*180
=
OpenStudy (anonymous):
n=28
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OpenStudy (anonymous):
so 540 is the sum of all interior angles but does that mean n = 28
OpenStudy (anonymous):
help?
OpenStudy (anonymous):
@hba help?
OpenStudy (hba):
135+62+151+140+n+n+6=540
Now solve for n.
OpenStudy (anonymous):
n= 28
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OpenStudy (hba):
Did you do it correctly ?
OpenStudy (hba):
Check it again.
OpenStudy (anonymous):
23
OpenStudy (hba):
Ok,good :)
OpenStudy (hba):
Now close it and if you have a new question post it in a new tab :)