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Mathematics 15 Online
OpenStudy (anonymous):

If

jimthompson5910 (jim_thompson5910):

|dw:1356993765795:dw|

OpenStudy (anonymous):

DO I have to draw that?

jimthompson5910 (jim_thompson5910):

So we can see that ABD is half of ABC ABD = (1/2)*ABC 2x+1 = (1/2)*(6x-22) 2x+1 = (1/2)*(6x)-(1/2)*22 2x+1 = 3x - 11 Keep going to solve for x

jimthompson5910 (jim_thompson5910):

no, but it helps if you don't see that ABD = (1/2)*ABC

OpenStudy (anonymous):

how do I solve for x?

jimthompson5910 (jim_thompson5910):

you have to isolate x, so you need move all the x terms to one side everything else gets moved to the other

jimthompson5910 (jim_thompson5910):

so the 3x needs to get moved to the left the +1 on the left side needs to move to the right side

OpenStudy (anonymous):

sso its -10?

OpenStudy (anonymous):

-11-1?

jimthompson5910 (jim_thompson5910):

not quite, you subtract 1 from both sides -11 - 1 = -12 so it's -12 on the right side

jimthompson5910 (jim_thompson5910):

on the left side, you go from 2x to 2x - 3x -1x -x So the left side becomes -x --------------------------------------- We therefore go from 2x+1 = 3x - 11 to -x = -12

OpenStudy (anonymous):

then what?

jimthompson5910 (jim_thompson5910):

-x = -12 so x = ???

OpenStudy (anonymous):

-12?

jimthompson5910 (jim_thompson5910):

no that's negative x negative x = negative 12 positive x = ???

OpenStudy (anonymous):

12?

jimthompson5910 (jim_thompson5910):

yep

OpenStudy (anonymous):

thanks(:

jimthompson5910 (jim_thompson5910):

np

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