Question

Factor y^3+6z^2-3y-18

Answer 1

@jim_thompson5910

Answer 2

I'm assuming that 'z' is really a 'y'

y^3+6y^2-3y-18

(y^3+6y^2)+(-3y-18)

y^2(y+6)-3(y+6)

(y^2-3)(y+6)

Answer 3

Oh yeah im so sorry

Answer 4

its ok

Answer 5

Thanks !