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5-x^4-4x^2=0
@hartnn can u help me with this well when i graphed it i got -1 and 1
is their any other teq
\[5-x^4-4x^2\]
put x^2=y 5-y^2-4y=0 solve this quadratic.
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and yes, only 2 real roots, -1 and 1 other 2 are imaginary roots.
i am getting 1 and -5
when i solved in ur method
yup, so x^2=1 ---->x= +1 or -1 x^2 = -5 ---->x=+i sqrt 5, -i sqrt 5 got it ?
yup thx
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welcome ^_^
whish ur family happy new year
behalf of me
happy new year to you and your family also :)
:-)
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