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What is the value of X?
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is it 6? a^2 + b^2 = c^2 / not sure what numbers to add.
\[\cos \theta =B/H\] \[\cos 60^0 =x/6\] Solve for x :)
Ohh okay I was thinking something else. trying to catch up on homework over the holiday break, my mother doesn't know anything about geometry. Thank you very much. :)
You're welcome :) I hope you know what is cos(60).
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