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f(x) 2sqrt{x} cutoff
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What ? \[f(x)=2\sqrt{2}\] What do you have to find ?
cutoff
sry!! what do u mean by (CutOFF) ?!!!
derived...
\[2\sqrt{x}\]
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hmmmm.... look f(x)=2sqrtx ........................ since 2sqrtx=2x^1/2 Therefore: f*(x)= (1/2.2).X^(1-1/2) Therefore f*(x)=X^-1/2=1/sqrtx
\[2\sqrt{x} = \frac{ 1 }{ 2\sqrt{x} }\] ic correct
No there is no 2 it will be \[\frac{1 }{ \sqrt{x} }\] only
ok
did u gt it or u want me to explain more ?!!
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no i got it
Ok
can u help me one question
Sure
wait one minute
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