Question

How do I find the intercepts of 4x^2+y=4

Answer 1

@AJQ

You have to find x and y intercept


Right ?

Answer 2

For x intercept y=0

For y intercept x=0

Best of luck :)

Answer 3

Yes and when I find the X- intercept I need to get rid of the exponent right?

Answer 4

Do I factor it out?

Answer 5

Show me your working :)

Answer 6

4x^2 + 0=4
4x^2-4=0
(2x+2) (2x-2)
2x+2=0; 2x-2=0
2x/2= -2/2
x=-1
2x/2=2/2
x=1

Answer 7

See this

4x^2=4

x^2=1

x=+-1

Got it ?

Answer 8

No how did you get x^2=1

Answer 9

divide 4 on both sides?

Answer 10

Yes.

Answer 11

I got it! Thanks!

Answer 12

When we remove the sqrt we get +- 1

Answer 13

You are welcome :)

Answer 14

You can press the best response button if you think my answer was the best :)

Answer 15

If you are done with the question please close it then :)