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OpenStudy (help!!!!):
the three digit # 49x is divisible by 4 with no remainders, if the sum of the digits is divisible by 5 with no remainders, what is the number?
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OpenStudy (anonymous):
Im not sure if theres a way to do this other than thinking about it.. 4+9=13 so if you add 2 that will satisfy the second requirement...now is 492 divisible by 4?
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