Question

What is the 46th term of the arithmetic series 1, 8, 15, … ?

181

243

316

422

Answer 1

looks like 7 at first but it not.......

Answer 2

Tn= a+(n-1)d

where Tn is the term , a = 1st term of Arithmetic progression d is common difference

Answer 3

so T46 = 1+(46-1)*7= 1+ (45*7) = 316

Answer 4

\[a_{n} = 1 + (n-1) \cdot 7 \implies a_{46} = 1 + (46-1)\cdot 7 = 316\]

Answer 5

Aw thanks guys! :)

Answer 6

sure