Question

What is the center and radius of the circle with the equation x2 + y2 + 8x – 12y + 36 = 0 ?

Center: (–4, 6); Radius = 4

Center: (–4, 6); Radius = 5

Center: (5, 6); Radius = 4

Center: (5, 6); Radius = 5

Answer 1

Group the x and y and move 36 to the other side

x^2+8x+y^2-12y=-36

now you need to complete the square of x^2+8x and y^2-12y

Answer 2

the center is (-4, 6) radius 4 ??

Answer 3

Yes

Answer 4

thanks :)