Question

Solve for X: 12/x^2-16 - 24/x-4 = 3

Answer 1

Using difference of squares:\[
(a^2-b^2) = (a-b)(a+b)
\]So: \[
(x^2-16) = (x^2-4^2) = (x-4)(x+4)
\]

Answer 2

Multiplying both sides by \((x-4)(x+4)\) you'd get: \[
12 - 24(x+4) = 3(x-4)(x+4)
\]So then it's just a matter of simplifying and stuff.

Answer 3

If you can get it in the form of \[
ax^2+bx+c = 0
\]Then your answer is just the quadratic formula: \[
x =\frac{-b \pm \sqrt{b^2-4ac}}{2a}
\]