Question

(algebra) Consider two numbers 24/x and 24/x+1 , where x is a positive integer. If the difference between the numbers is 1/3.
A) show that x²+x -72 = 0
B) Hence find the value of X, where X=0 and X is a positive integer.

Answer 1

if the difference of the two numbers is \(\frac{1}{3}\) you can write
\[\frac{24}{x}=\frac{24}{x+1}+\frac{1}{3}\]

Answer 2

how do u do the 24/x thing?

Answer 3

thx btw *

Answer 4

\frac{a}{b}