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OpenStudy (anonymous):
Factor completely: 4x2 + 25x + 6
(4x + 1)(x + 6)
(4x + 6)(x + 1)
(2x + 3)(2x + 2)
(2x + 6)(2x + 1)
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OpenStudy (ash2326):
@Solmyr Did you try this?
OpenStudy (anonymous):
sadly no cause i have no idea of how to do it
OpenStudy (anonymous):
i was looking for someone to show me how to do it
OpenStudy (ash2326):
Ok, I'll explain you
OpenStudy (ash2326):
General quadratic equation
\[ax^2+bx+c=0\]
Here we have
\[4x^2+25x+6\]
So what's a , b and c here?
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OpenStudy (anonymous):
a=4
b=25
c=6
OpenStudy (ash2326):
Good, first step is to find the product of a and c
What is it here?
OpenStudy (anonymous):
4*6=24
OpenStudy (ash2326):
Now b is 25 here
Can you find factors of 24, which add up or subtract to form 24 ?
OpenStudy (anonymous):
2,4,6,8
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OpenStudy (anonymous):
12
OpenStudy (ash2326):
Let me rephrase it, 2 factors of 24 which add up or subtract to form 25?
OpenStudy (anonymous):
im not sure
OpenStudy (ash2326):
Check if 24 and 1 satisfy that??
OpenStudy (anonymous):
ok i guess it does
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OpenStudy (ash2326):
so write 25x as 24x and 1x
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i have to do something ill brb
OpenStudy (ash2326):
\[4x^2+24x+x+6=0\]
OpenStudy (anonymous):
im back
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