Question

Factor completely: 18x2 − 21x − 15

3(2x + 1)(3x − 5)

3(2x − 5)(3x + 1)

3(2x − 1)(3x + 5)

3(6x + 1)(x − 5)

Answer 1

First, factor out the constant of 3 to get \[3(x^2-7x-5)\]

Answer 2

ok

Answer 3

Then factor x^2-7x-5

Answer 4

i mean 6x^2-7x-5

Answer 5

36x - 7x - 5

Answer 6

Then you will get \[3(2x+1)(3x-5)\]

Answer 7

oh

Answer 8

thank you