Question

Factor completely: 3x2 + 2x − 1

(3x + 1)(x − 1)

(3x + 1)(x + 1)

(3x − 1)(x + 1)

(3x − 1)(x − 1)

Answer 1

First break the middle term such that when it is added it becomes \(2x\) & when multiplied, we get the product of \(3x^2\) & \(1\).

\(\Large{\implies3x^2+3x-x-1}\)
\(\Large{\implies3x(x+1)-1(x+1)}\)
\(\Large{\implies(3x-1)(x+1)}\)

Answer 2

Gt it ???