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Mathematics 11 Online
OpenStudy (anonymous):

Can someone explain to me how this is true? Very simple differential.

OpenStudy (anonymous):

\[\frac{ 1 }{(1-x)^{2} }=\frac{ d }{ dx }\frac{ 1 }{ 1-x }=\frac{ d }{ dx }\sum_{n=0}^{\infty}x^{n}=\sum_{n=0}^{\infty}(n+1)x^{n}\]

OpenStudy (anonymous):

What is the problem?

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