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Mathematics 6 Online
OpenStudy (anonymous):

question:

OpenStudy (anonymous):

OpenStudy (anonymous):

what's the value of x?

OpenStudy (hba):

Use Pythogras thorem :) H^2=P^2+B^2

OpenStudy (hba):

@needmathhelp7 Just put in the values and find x :)

OpenStudy (hba):

|dw:1357201580903:dw|

OpenStudy (hba):

P^2=H^2-B^2 @needmathhelp7 Now please solve :)

OpenStudy (anonymous):

do you subtract or add them?

OpenStudy (hba):

@needmathhelp7 subtract them :)

OpenStudy (anonymous):

so 784-196= 588?

OpenStudy (anonymous):

24,24

OpenStudy (anonymous):

wait, what's 24?

OpenStudy (hba):

P^2=588 Now take underroot :)

OpenStudy (anonymous):

\[\sqrt{588}\]=24.24

OpenStudy (anonymous):

Ohhh :)

OpenStudy (hba):

\[\sqrt{P^2}=\sqrt{588}\]

OpenStudy (anonymous):

so x = 24.24?

OpenStudy (hba):

x=24.24 that is your answer ::)

OpenStudy (anonymous):

yea:)

OpenStudy (anonymous):

awesome thank you! :)

OpenStudy (hba):

Yeah you nailed it right and kaboom got x ;)

OpenStudy (hba):

Welcome :)

OpenStudy (anonymous):

sry cause of interrupting!:|

OpenStudy (hba):

It's fine :)

OpenStudy (anonymous):

@hba kindly answer!

OpenStudy (hba):

\[\Huge \text{♛HBA™}♛\]

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