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what's the value of x?
Use Pythogras thorem :) H^2=P^2+B^2
@needmathhelp7 Just put in the values and find x :)
|dw:1357201580903:dw|
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P^2=H^2-B^2 @needmathhelp7 Now please solve :)
do you subtract or add them?
@needmathhelp7 subtract them :)
so 784-196= 588?
24,24
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wait, what's 24?
P^2=588 Now take underroot :)
\[\sqrt{588}\]=24.24
Ohhh :)
\[\sqrt{P^2}=\sqrt{588}\]
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so x = 24.24?
x=24.24 that is your answer ::)
yea:)
awesome thank you! :)
Yeah you nailed it right and kaboom got x ;)
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Welcome :)
sry cause of interrupting!:|
It's fine :)
@hba kindly answer!
\[\Huge \text{♛HBA™}♛\]
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