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OpenStudy (anonymous):
Find x > 3 such that ln(x) < x^(0.1)
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OpenStudy (anonymous):
My guess? \[ \ln(x) < x^{0.1} \\ \ln(x) - x^{0.1} < 0 \] Then use newton's iterative method of finding roots. They're both increasing functions.
OpenStudy (anonymous):
Yeah, thats what i was thinking.. thanks!
OpenStudy (anonymous):
No problem
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