Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

Find x > 3 such that ln(x) < x^(0.1)

OpenStudy (anonymous):

My guess? \[ \ln(x) < x^{0.1} \\ \ln(x) - x^{0.1} < 0 \] Then use newton's iterative method of finding roots. They're both increasing functions.

OpenStudy (anonymous):

Yeah, thats what i was thinking.. thanks!

OpenStudy (anonymous):

No problem

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!