Question

What is the focus of the parabola y = 1/8 (x – 2)(^2) – 4

Answer 1

i got this

Answer 2

We want it in the form: \[ \large
4p(y-k)=(x-h)^2
\]

Answer 3

wrong thing
y=1/8(x-2)^2 -4
+4 +4

y+4 =1/8(x-2)^2
*8 *8

8(y+4) = (x-2)^2

(4*2) (y+4) = (x-2)^2

Answer 4

The vertex is \((h, k)\) and focus is \((h, k+p)\)

Answer 5

So that would make the focus (2, -2)

Answer 6

And directrix is \(y = k-p\).

Answer 7

u get it

Answer 8

@FlyinSolo_424

Answer 9

thank you I get it

Answer 10

needed to freshen up