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3x+2(6-x)<42-4x
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if x=6 then would it be written as ... [6,0)
3x+12-2x<42-4x
3x-2x+4x<42-12
\[[\infty,6)\]
5x<30 then divide by 5 both side
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That was very rude of you to close the question while I was answering it :(
seriously ... i don't need lectures, i need math help ..
If you go back into the "Closed Questions" you will see a complete detailed solution to help you learn math.
here it is worked out by WA steph http://www.wolframalpha.com/input/?i=3x%2B2%286-x%29%3C42-4x
i think it does a better job explaining than i could
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thanks so mjuch
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